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If m things are distributed among a men and b women. Then the probability that number of things received by men is odd is

A

`1/2[((b+a)^(m)+(b-a)^(m))/((b+a)^(m))]`

B

`1/2[(a+b)^(m)/((a-b)^(m))]`

C

`1/2[((b+a)^(m)-(b-a)^(m))/((b+a)^(m))]`

D

Data inadequate

Text Solution

Verified by Experts

The correct Answer is:
C
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