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2 cards are selected randomly from a pac...

2 cards are selected randomly from a pack of 52 cards. The probability that the first card is a club and second is not a king, is

A

`82/221`

B

`41/221`

C

`1/221`

D

`4/17`

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The correct Answer is:
To solve the problem of finding the probability that the first card drawn is a club and the second card drawn is not a king, we can break it down into steps. ### Step 1: Understand the total number of cards A standard deck of cards has 52 cards, which consist of 4 suits: clubs, diamonds, hearts, and spades. Each suit has 13 cards. **Hint:** Remember that there are 52 cards in total, divided equally among 4 suits. ### Step 2: Calculate the probability of drawing a club first The number of clubs in a deck is 13. Therefore, the probability of drawing a club first is: \[ P(\text{First card is a club}) = \frac{13}{52} = \frac{1}{4} \] **Hint:** The probability of an event is the number of favorable outcomes divided by the total number of outcomes. ### Step 3: Calculate the probability of drawing a non-king second After drawing the first card (which is a club), there are now 51 cards left in the deck. We need to consider two scenarios for the second card: 1. If the first card was a club but not a king (12 clubs are not kings). 2. If the first card was the king of clubs (1 club is a king). **Case 1:** First card is a club but not a king. - If the first card is one of the 12 non-king clubs, there are still 4 kings remaining among the 51 cards. Thus, the number of non-kings left is \(51 - 4 = 47\). - The probability for this case is: \[ P(\text{Second card is not a king | First card is a non-king club}) = \frac{47}{51} \] **Case 2:** First card is the king of clubs. - If the first card is the king of clubs, there are now 3 kings left among the 51 cards. Thus, the number of non-kings left is \(51 - 3 = 48\). - The probability for this case is: \[ P(\text{Second card is not a king | First card is the king of clubs}) = \frac{48}{51} \] ### Step 4: Combine the probabilities Now, we can combine the probabilities from both cases using the law of total probability: 1. Probability of first card being a non-king club and second card not being a king: \[ P(\text{Non-king club}) \times P(\text{Not a king | Non-king club}) = \frac{12}{52} \times \frac{47}{51} \] 2. Probability of first card being the king of clubs and second card not being a king: \[ P(\text{King of clubs}) \times P(\text{Not a king | King of clubs}) = \frac{1}{52} \times \frac{48}{51} \] ### Step 5: Calculate the total probability Now, we can calculate the total probability: \[ P(\text{First card is a club and second is not a king}) = \left(\frac{12}{52} \times \frac{47}{51}\right) + \left(\frac{1}{52} \times \frac{48}{51}\right) \] Calculating each term: 1. For the first term: \[ \frac{12 \times 47}{52 \times 51} = \frac{564}{2652} \] 2. For the second term: \[ \frac{1 \times 48}{52 \times 51} = \frac{48}{2652} \] Now, adding these two fractions: \[ \frac{564 + 48}{2652} = \frac{612}{2652} \] ### Step 6: Simplify the fraction Now, we simplify \(\frac{612}{2652}\): \[ \frac{612 \div 12}{2652 \div 12} = \frac{51}{221} \] Thus, the final answer is: \[ \text{Probability that the first card is a club and the second is not a king} = \frac{51}{221} \] ### Summary of Steps 1. Understand the total number of cards. 2. Calculate the probability of drawing a club first. 3. Calculate the probability of drawing a non-king second based on the first card drawn. 4. Combine the probabilities from both cases. 5. Calculate and simplify the total probability.
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