Home
Class 12
MATHS
Delegates of the five of the member coun...

Delegates of the five of the member countries of SAARC decide to hold a round table conference. There are 2 Indians, 2 Bangladeshis, 2 Pakistanis, 2 Srilankans and 2 Nepalis. The probability that people of same nationality sit together is

A

`(3!xx(2!)^(5))/(9!)`

B

`2/189`

C

`((4!)xx(2!)^(5))/(9!)`

D

`2/945`

Text Solution

AI Generated Solution

The correct Answer is:
To find the probability that delegates of the same nationality sit together at a round table, we can follow these steps: ### Step 1: Determine the total number of delegates We have: - 2 Indians - 2 Bangladeshis - 2 Pakistanis - 2 Sri Lankans - 2 Nepalis Total number of delegates = 2 + 2 + 2 + 2 + 2 = 10 delegates. ### Step 2: Calculate the total arrangements around a round table For n people sitting around a round table, the number of arrangements is given by (n - 1)!. Here, n = 10, so the total arrangements = (10 - 1)! = 9! = 362880. ### Step 3: Group delegates of the same nationality If we consider each pair of delegates from the same country as a single unit, we can treat them as 5 units: - 1 unit for Indians (2 Indians) - 1 unit for Bangladeshis (2 Bangladeshis) - 1 unit for Pakistanis (2 Pakistanis) - 1 unit for Sri Lankans (2 Sri Lankans) - 1 unit for Nepalis (2 Nepalis) ### Step 4: Calculate arrangements of these units around the table Now, we have 5 units to arrange around the table. The number of arrangements for these 5 units is (5 - 1)! = 4! = 24. ### Step 5: Arrange delegates within each unit Within each unit, the 2 delegates can be arranged in 2! ways. Since there are 5 units, the total arrangements within the units will be (2!)^5 = 2^5 = 32. ### Step 6: Calculate the total favorable arrangements The total favorable arrangements where delegates of the same nationality sit together is given by: Total favorable arrangements = arrangements of units × arrangements within units = 4! × (2!)^5 = 24 × 32 = 768. ### Step 7: Calculate the probability The probability that delegates of the same nationality sit together is given by: Probability = (Total favorable arrangements) / (Total arrangements) = 768 / 362880. ### Step 8: Simplify the probability To simplify: 768 / 362880 = 1 / 472.5 (approximately). Thus, the final probability that delegates of the same nationality sit together is approximately 1/472.5. ### Final Answer The probability that people of the same nationality sit together is approximately 1/472.5. ---
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - D Linked Comprehension Type Questions)|20 Videos
  • PROBABILITY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-E (assertion -reason type questions)|14 Videos
  • PROBABILITY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - B Objective Type Questions (One option is correct))|64 Videos
  • PRINCIPLE OF MATHEMATICAL

    AAKASH INSTITUTE ENGLISH|Exercise Section-D:(Assertion-Reason Type Questions)|11 Videos
  • RELATIONS AND FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - J) Aakash Challengers Questions|8 Videos

Similar Questions

Explore conceptually related problems

4 five-rupee coins, 3 two-rupee coins and 2 one-rupee coins are stacked together in a column at random. The probability that the coins of the same denomination are consecutive is

Find the probability of product of a perfect square when 2 dice are thrown together.

If 5 positive integers are taken at random and multiplied together. The probability that the last digit of the product is 2,4,6,8 is

An almirah stores 5 black and 4 white socks well mixed. A boy pulls out 2 socks at random. The probability that 2 are of the same colour is

Six '+' signs and five '-' signs are to be arranged in a row. If the arrangement is at random, then the probability that no 2 '-' sings are together, is

Five coins whose faces are marked 2, 3 are thrown. What is the probability of obtaining a total of 12?

An oridinary cube has four faces, one face marked 2 another marked 3, Then the probability of obtaining a total of exactly 12 in five throws is

A five digit number if formed by the digits 1,2,3,4,5,6 and 8. The probability that the number has even digit at both ends is

Given the probability that A can solve a problem is 2/3 and the probability that B can solve the same problem is 3/5. Find the probability that none of the two will be able to solve the problem.

There are 2 vans each having numbered seats, 3 in the front and 4 at the back. There are 3 girls and 9 boys to be seated in the vans. The probablity of 3 girls sitting together in a back row on adjacent seats, is

AAKASH INSTITUTE ENGLISH-PROBABILITY-ASSIGNMENT (SECTION - C Objective Type Questions (More than one options are correct))
  1. There are 7 seats in a row. Three persons take seats at random the pro...

    Text Solution

    |

  2. Box A has 3 white and 2 red balls, box B has 2 white and 4 red balls. ...

    Text Solution

    |

  3. If P(A) = 2/3, P(B) = 4/9 and P(AcapB)=cap, then P(A'capB') is greater...

    Text Solution

    |

  4. If A and B are two events such that P(A cup B) =3/4 ,P(A cap B) = 1/4 ...

    Text Solution

    |

  5. Two dices are rolled and numbers r(1) and r(2) are chosen. Let 1+omega...

    Text Solution

    |

  6. Delegates of the five of the member countries of SAARC decide to hold ...

    Text Solution

    |

  7. If a Grand father along with his two grandsons and four grand daughter...

    Text Solution

    |

  8. A quadratic equation is cjoen from the set of all quadratic equations...

    Text Solution

    |

  9. A sample space consists of 3 sample points with associated probabili...

    Text Solution

    |

  10. If A and B are two independent events such that P(barAnnB)=2//15and P(...

    Text Solution

    |

  11. For two events A and B let, P(A)=(3)/(5), P(B)=(2)/(3), then which of ...

    Text Solution

    |

  12. An unbiased coin is tossed n times. Let X denote the number of times h...

    Text Solution

    |

  13. A fair coin is tossed 99 times. Let X be the number of times heads occ...

    Text Solution

    |

  14. Consider the following events for a family with children A = {Childr...

    Text Solution

    |

  15. A fair coin is tossed three times. Consider the events A = {First to...

    Text Solution

    |

  16. Two events A and B are such that P(A)=1/4,P(A//B)=1/2 and P(B//A)=2/3 ...

    Text Solution

    |

  17. A, B, C in order roll a dice on the condition that one who gets a six,...

    Text Solution

    |

  18. There are 3 men, 2 women and 4 children. If 4 persons are selected the...

    Text Solution

    |

  19. If the letters of word ASSASSIN are written at random in a raw, then w...

    Text Solution

    |

  20. If alphabets of word RAKESH are written in given boxes, then probabili...

    Text Solution

    |