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Two players P(1)and P(2) are playing the...

Two players `P_(1)and P_(2)` are playing the final of a chess championship, which consists of a series of matches. Probability of `P_(1)` winning a matic is 2/3 and that of `P_(2) ` is 1/3. Thus winner will be the one who is ahead by 2 games as compared to the other player and wins at least 6 games. Now, if the player `P_(2)` wins the first four matches, find the probability of `P_(1)` wining the championship.

A

`1077/3645`

B

`1088/3645`

C

`1099/3645`

D

`1000/3645`

Text Solution

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The correct Answer is:
A
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