A bus starts from rest and moves down a hill with constant acceleration. The bus travels a distance of 400 m in 10 second. If mass of the bus is 5 metric tonne, then what will be its acceleration and force acting on it? (1 metric tonne = 1000 kg)

Explanation

We have
u=0
s= 400 m
t = 10 s
Mass, m = 5 metri tonne
= 5000 Kg
By using s = ` ut + 1/2 at^(2) , ` we get
` 400 = 0xx 10 + 1/2 a(10)^(2)`
` :. a = (400 xx 2)/100 = 8 "m//s^(2)`
Now , as we know
`F=ma`
` :. F = 5000 xx 8 = 40,000 N`
Thus , force acting on bus is 40,000 N.