A stone of mass 1 kg is thrown with a velocity of 20 m/s across the frozen surface of a take and it comes to rest after travelling a distance of 50 m . What is the magnitude of the force opposing the motion of the stone ?

Explanation

To solve the problem step by step, we can follow these calculations:

### Step 1: Identify the known values
- Mass of the stone (m) = 1 kg
- Initial velocity (u) = 20 m/s
- Final velocity (v) = 0 m/s (since it comes to rest)
- Distance traveled (s) = 50 m

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