A block of mass 5 kg rests on a inclined plane at an angle of `30^(@)` with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

Explanation

To solve the problem of finding the coefficient of static friction between a block of mass 5 kg resting on an inclined plane at an angle of 30 degrees with the horizontal, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Forces Acting on the Block:**
- The weight of the block (W) acts downward and is given by \( W = mg \), where \( m = 5 \, \text{kg} \) and \( g = 9.8 \, \text{m/s}^2 \).
- The weight can be resolved into two components:
- **Parallel to the incline:** \( W_{\parallel} = mg \sin \theta \)
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