A cubical box of side `1 m` contains helium gas (atomic weight 4) at a pressure of `100 N//m^2`. During an observation time of `1 second`, an atom travelling with the root - mean - square speed parallel to one of the edges of the cube, was found to make `500 hits` with a particular wall, without any collision with other atoms . Take `R = (25)/3 j //mol - K and k = 1.38 xx 10^-23 J//K`.
Evaluate the total mass of helium gas in the box.

A cubical box of side 1 m contains helium gas (atomic weight 4) at a pressure of 100 N//m^2 . During an observation time of 1 second , an atom travelling with the root - mean - square speed parallel to one of the edges of the cube, was found to make 500 hits with a particular wall, without any collision with other atoms . Take R = (25)/3 j //mol - K and k = 1.38 xx 10^-23 J//K . Evaluate the temperature of the gas.

A cubical box of side 1 m contains helium gas (atomic weight 4) at a pressure of 100 N//m^2 . During an observation time of 1 second , an atom travelling with the root - mean - square speed parallel to one of the edges of the cube, was found to make 500 hits with a particular wall, without any collision with other atoms . Take R = (25)/3 j //mol - K and k = 1.38 xx 10^-23 J//K . (a) Evalite the temperature of the gas. (b) Evaluate the average kinetic energy per atom. ( c) Evaluate the total mass of helium gas in the box.

A cubical box of side 1 meter contains helium gas (atomic weight 4) at a pressure of 100N//m^2. During and observation time of 1 second, an atom travelling with the root-mean-square speed parallel to one of the edges of the cube, was found to make 500 hits with a particular wall, without any collision with other atoms. Take R=25/3 Jmole-K and k=1.38xx10^-23J//K Evaluate the average kinetic energy per atom.

Calculate the number of atoms and volume of 1g helium gas at STP

The root mean square velocity of the gas molecule is 300 m/s. What will be the root mean square speed of he molecule if the atomic weight is doubled and absolute temperature is halved ?

The weight of 350 ml a diatomic gas at 0^(@)C and 2atm pressure is 1 gm.The weight of one atom is :-

The root mean square speed of the molecules of a diatomic gas is v. When the temperature is doubled, the molecules dissociates into two atoms. The new root mean square speed of the atom is

A mixture of two gases is contained in a vessel. The Gas 1 is monoatomic and gas 2 is diatomic and the ratio of their molecular masses M 1 ​ /M 2 ​ =1/4. the ratio of root mean square speeds of the molecules of two gases is

The density of carbon dioxide gas at 27^(@)C and at pressure 1000 N//m^(2) is 1 kg m^(-3) . Find the root mean square speed of its molecule at 0^(@)C . (pressure is constant)

The root mean square speed fo molecules of nitrogen gas is v at a certain temperature. When the temperature is doubled, the molecules dissociate into individual atoms. The new rms speed of the atom is: