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A gaseous mixture enclosed in a vessel c...

A gaseous mixture enclosed in a vessel consists of `1 g` mole of a gas `A` with `gamma - 5//3` and another `B` with `gamma = 7//5` at a temperature `T`. The gases `A` and `B` do not react with each other and are assumed to be ideal. Find the number of gram moles of gas if `gamma` of the gaseous mixture is `19//13`.

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A gaseous mixture enclosed in a vessel consists of one gram mole of a gas A with gamma=(5/3) and some amount of gas B with gamma=7/5 at a temperature T. The gases A and B do not react with each other and are assumed to be ideal. Find the number of gram moles of the gas B if gamma for the gaseous mixture is (19/13) .

A gaseous mixture enclosed in a vessel consists of one gram mole of a gas A with gamma=(5/3) and some amount of gas B with gamma=7/5 at a temperature T. The gases A and B do not react with each other and are assumed to be ideal. Find the number of gram moles of the gas B if gamma for the gaseous mixture is (19/13) .

Knowledge Check

  • A gaseous mixture enclosed in a vessel consists of one gram mole of a gas A with gamma=(5/3) and some amount of gas B with gamma=7/5 at a temperature T. The gases A and B do not react with each other and are assumed to be ideal. Find the number of gram moles of the gas B if gamma for the gaseous mixture is (19/13) .

    A
    2
    B
    12
    C
    16
    D
    8

  • 1 mole of a gas with gamma=7//5 is mixed with 1 mole of a gas with gamma=5//3 , then the value of gamma for the resulting mixture is

    A
    `7/5`
    B
    `2/5`
    C
    `3/2`
    D
    `(12)/(7)`

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    A gaseous mixture enclosed in a vessel of volume V consists of one mole of a gas A with gamma=(C_p//C_v)=5//3 and another gas B with gamma=7//5 at a certain temperature T. The relative molar masses of the gasses A and B are 4 and 32, respectively. The gases A and B do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation PV^(19//13)=constant , in adiabatic processes. (a) Find the number of moles of the gas B in the gaseous mixture. (b) Compute the speed of sound in the gaseous mixture at T=300K . (c) If T is raised by 1K from 300K, find the % change in the speed of sound in the gaseous mixture. (d) The mixtrue is compressed adiabatically to 1//5 of its initial volume V. Find the change in its adaibatic compressibility in terms of the given quantities.

    A gaseous mixture enclosed in a vessel of volume V consists of one mole of gas A with gamma = (C_(P))/(C_(V)) = (5)/(3) an another gas B with gamma = (7)/(5) at a certain temperature T . The gram molecular weights of the gases A and B are 4 and 32 respectively. The gases A and B do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation PV^(19//13) = constant , in adiabatic process. Find the number of moles of the gas B in the gaseous mixture.

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