A rectangular surface of sides `10 cm and 15 cm` is palaced inside a uniform electric field fo `25 Vm^(-1)`, such that normal to the surface makes an angle of `60^(@)` with the direction of electric field. Find the flux of electric field through the rectangular surface.

Explanation

To find the electric flux through the rectangular surface, we can use the formula for electric flux, which is given by:

\[ \Phi = E \cdot A \cdot \cos(\theta) \]

where:
- \(\Phi\) is the electric flux,
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