An electric dipole of length 10cm having charges `+- 6xx10^(-3) C`, placed at `30^(@)` with respect to a uniform electric field experiences a torque of magnitude `6 sqrt(3) N-m`. Calculate (i) magnitude of electric field (ii) the potential energy of dipole.

Explanation

To solve the problem step by step, we will calculate the magnitude of the electric field and the potential energy of the dipole.

### Given Data:
- Length of the dipole, \( l = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Charge of the dipole, \( q = 6 \times 10^{-3} \, \text{C} \)
- Angle with respect to the electric field, \( \theta = 30^\circ \)
- Torque experienced by the dipole, \( \tau = 6\sqrt{3} \, \text{N-m} \)

...