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Two chargeed metallic spheres of same ...

Two chargeed metallic spheres of same size repel each other by a force F. They are now touched with each other and are then separated to same initial distance. Now the force of repulsion is F'. Which of the following are possible?

A

A. `F' = F `

B

B. `F' lt F`

C

C. `F' cancel(=)F`

D

D. `F' lt F `

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the situation involving two charged metallic spheres that repel each other with a force \( F \). After touching each other and then being separated, we need to determine the new force of repulsion \( F' \) and how it relates to the original force \( F \). ### Step-by-Step Solution: 1. **Understanding the Initial Conditions**: - Let the charges on the two spheres be \( q_1 \) and \( q_2 \). - The initial force of repulsion \( F \) between the two spheres can be expressed using Coulomb's Law: \[ F = k \frac{|q_1 q_2|}{r^2} \] where \( k \) is Coulomb's constant and \( r \) is the distance between the centers of the spheres. 2. **Touching the Spheres**: - When the two spheres are touched, the charges redistribute equally because they are identical in size. The new charges on each sphere after touching will be: \[ q' = \frac{q_1 + q_2}{2} \] - Therefore, both spheres will have the same charge \( q' \) after they are separated. 3. **Calculating the New Force of Repulsion**: - After the spheres are separated again to the same distance \( r \), the new force of repulsion \( F' \) can be calculated as: \[ F' = k \frac{|q' q'|}{r^2} = k \frac{\left(\frac{q_1 + q_2}{2}\right)^2}{r^2} \] - Expanding this gives: \[ F' = k \frac{(q_1 + q_2)^2}{4r^2} \] 4. **Comparing \( F' \) with \( F \)**: - We can express \( F' \) in terms of \( F \): \[ F' = \frac{(q_1 + q_2)^2}{4|q_1 q_2|} F \] - Depending on the values of \( q_1 \) and \( q_2 \), we can analyze the relationship between \( F' \) and \( F \): - If \( q_1 = q_2 \), then \( F' = F \). - If \( q_1 \neq q_2 \), \( F' \) could be greater than \( F \) or less than \( F \) depending on the specific values of \( q_1 \) and \( q_2 \). 5. **Conclusion**: - The possible relationships between \( F' \) and \( F \) are: - \( F' = F \) (if both charges are equal) - \( F' > F \) (if the charges are not equal) - \( F' \neq F \) (in general, after touching, the forces will not be equal unless the charges were initially equal). ### Possible Answers: Based on the analysis: - Option A: \( F' = F \) (possible if charges are equal) - Option B: \( F' > F \) (possible if charges are not equal) - Option C: \( F' \neq F \) (generally true)
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Knowledge Check

  • Two insulated charged metallic spheres P and Q have their centres separated by a distance of 60 cm. The radii of P and Q are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is 3.2xx10^(-7)C is

    A
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    B
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    C
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    D
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