Planes x= 2 and y = -3 , respectively , carry charge densities`10 nC //m^(2)`. If the line x=0,z=2 carries charge density `10 pi n C //m`, calculate the electric field vector at `( 1,1 ,-1)`.

Explanation

To find the electric field vector at the point (1, 1, -1) due to the given charge distributions, we will follow these steps:

### Step 1: Identify the charge distributions
We have:
1. A plane at \(x = 2\) with a charge density of \(10 \, \text{nC/m}^2\).
2. A plane at \(y = -3\) with a charge density of \(10 \, \text{nC/m}^2\).
3. A line at \(x = 0, z = 2\) with a linear charge density of \(10\pi \, \text{nC/m}\).

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