A metallic sphere of radius R is cut in two parts along a plane whose minimum distance from the sphere's centre is `h=R/2` and the sphere is uniformly charges by a total charged by a total electric charge Q. The minimum force necessary (to be applied on each of the two parts) to hold the two parts of the sphere together is `(3kQ^(2))/(p R^(2))`. Then find the value of p ?

Explanation

To solve the problem step by step, we will analyze the situation of the metallic sphere that is uniformly charged and cut into two parts. We will derive the minimum force necessary to hold the two parts together and find the value of \( p \).

### Step-by-Step Solution:

1. **Understanding the Problem:**
- We have a metallic sphere of radius \( R \) uniformly charged with total charge \( Q \).
- The sphere is cut into two parts along a plane that is at a minimum distance \( h = \frac{R}{2} \) from the center of the sphere.

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