For the following arrangement, find the equivalent capacitance between A and B
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Explanation

Here, the `3 mu F, 4 mu F ` and `5 mu F` capacitors are in series.
`:. C _(eq) = ((1)/(3) + (1)/(4) + (1)/(5))^(-1) = ( 60)/( 12+ 20 + 15)= ( 60 )/( 47)mu F`
Now, `2 mu F` and `( 60 )/( 47)` are in parallel , so we have
`C_(eq)= C_(1)+C_(2) = ( 154)/( 47) mu F`