The distance between the two plates of a cathode-ray oscilloscope is 1 cm and the potential difference between them is 1200 V. If an electron of energy 2000 eV enters at right angles to the field, what will be its deflection if the plate be 1.5 cm long.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the Electric Field (E)
The electric field between the plates of the cathode-ray oscilloscope can be calculated using the formula:

\[ E = \frac{V}{D} \]
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