Home
Class 12
PHYSICS
In a region of uniform electric field as...

In a region of uniform electric field as an electron travels from A to B it slows from `U_(A)=6.1xx10^(6)m//s "to" U_(B)=4.5xx10^(6)` m/s . What is its potential change `Delta V= V_(B)-V_(A)` in volts ?

A

18

B

`-18`

C

`+48`

D

`-48`

Text Solution

Verified by Experts

Answer (4)
`DeltaU + Delta K = 0`
`implies - e DeltaV + (1)/(2) m ( u_(B)^(2) - u_(A)^(2))=0`
`DeltaV = ((1)/(2) m(u_(B) ^(2) - u_(A)^(2)))/(e ) = ((1)/(2) xx 9.1 xx 10^(-31) xx 10^(12) [ 4.5 ^(2) - 6.1 ^(2)])/(1.6 xx 10^(-10))`
`=- 48.23 V`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-A) Objective Type Questions (Only one answer)|53 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-B (OBJECTIVE TYPE QUESTIONS (ONLY ONE ANSWER) )|1 Videos
  • ELECTROMAGNETIC WAVES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D Assertion-Reason Type Questions|25 Videos
  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D (ASSERTION-REASON TYPE QUESTIONS)|15 Videos

Similar Questions

Explore conceptually related problems

In uniform electric field E=10 N//C , find a. V_A-V_B , b. VB-V_C

An electron moving near an atomic nucleus has a speed of 6xx10^(6) +- 1% m//s . What is the uncertainty in its position?

The electron in a hydrogen atom moves in circular orbit of radius 5xx10^(-11)m with a speed of 0.6pixx10^(6)m//s then

An electron traveling in a uniform electric field passes from a region of potential V_1 to a region of higher potential V_2 . Then

In moving from A to B along an electric field line, the work done by the electric field on an electron is 6.4 xx 10^-19 J . If phi_1 and phi_2 are equipotential surfaces, then the potential difference V_C - V_A is. .

In uniform electric field, E = 10 NC^(-1) as shown in figure, find (i) V_(A)-V_(B) (ii) V_(B)-V_(C) .

Find the change in electric potential energy , Delta U as a charge of (a) 2.20 xx 10^(-6) C. (b) - 1.10 xx 10^(-6) C moves from a point A to a point given that the change in electric potential between these points is DeltaV= V_(B) -V_(A) = 24.0 V

At some instant the velocity components of an electron moving between two charged parallel plates are v_x=1.5xx10^5m//s and v_y=3.0xx10^6 m//s .Suppose that the electric field between the plates is given by E = (120 N//C) hatj . (a) What is the acceleration of the electron? (b) What will be the velocity of the electron after its x-coordinate has changed by 2.0 cm?

In a certain region of space a uniform and constant electric field and a magnetic field parallel to each other are present. A proton is fired from a point A in the field with speed V=4xx10^(4)m//s at an angle of alpha with the field direction. The proton reaches a point B in the field where its velocity makes an angle beta with the field direction. If (sinalpha)/(sinbeta)=sqrt3. Find the electric potential difference between the points A and B. Take mp (mass of proton) =1.6xx10^(-27) kg and e (magnitude of electronic charge) =1.6xx10^(-19) C.