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Consider two capacitors C(1)=10 mu F an...

Consider two capacitors `C_(1)=10 mu F ` and `C_(2) = 40 mu` F . What is the equivalent capacitance it the two are connected
(1) In parallel ?
(2) In series ?
(3) If the two are connected in series to a 9.0 volt battery what are the charge `Q_(1) ` and `Q_(2)` stored on the two capacitors ?

Text Solution

Verified by Experts

(a) `C_(eq) = C_(1)=C_(2) = 10 + 40 = 50 muF`
(b) `C_(eq) = ( C_(1) C_(2))/( C_(1)+C_(2)) = ( 10 xx 40 )/( ( 10+ 40)) = ( 400)/( 500 = 8 mu F`
(c ) `Q = C_(eq) V = 8 xx 9 = 72 mu C`
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