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In the arrangement C(1) = 10 mu, F C(2)=...

In the arrangement `C_(1) = 10 mu, F C_(2)= 10 mu F ` and `C_(3)= 20 mu F ` . What is the equivalent capacitance ( in `mu F` ) between points A and B ?

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Answer (1)
`C_(AB) = ( C_(1)(C_(2)+C_(3)))/(C_(1)+C_(2)+C_(3)) = ( 10( 10+ 20))/( 10+10+20)= ( 300)/( 40) =7.5 mu F`
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