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STATEMENT-1 : Inside an isolated hollow ...

STATEMENT-1 `:` Inside an isolated hollow spherical shell of charge, electrostatic potential is constant everywhere
and
STATEMENT-2 `:` Electric field inside a hollow spherical shell of charge is always zero.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False , Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both statements regarding the electrostatic potential and electric field inside a hollow spherical shell of charge. ### Step-by-Step Solution: 1. **Understanding the Hollow Spherical Shell**: - Consider an isolated hollow spherical shell with a uniform charge \( Q \) distributed over its surface. 2. **Analyzing Statement 2**: - **Statement 2** claims that the electric field inside a hollow spherical shell of charge is always zero. - According to Gauss's Law, the electric field \( E \) inside a closed surface is proportional to the charge enclosed by that surface. - Since all the charge \( Q \) resides on the surface of the shell, the charge enclosed within any Gaussian surface drawn inside the shell is zero. - Therefore, by Gauss's Law, the electric field \( E \) inside the hollow shell is indeed zero. - **Conclusion**: Statement 2 is **true**. 3. **Analyzing Statement 1**: - **Statement 1** states that the electrostatic potential inside the hollow spherical shell is constant everywhere. - The relationship between electric field \( E \) and electrostatic potential \( V \) is given by: \[ E = -\frac{dV}{dr} \] - Since we have established that the electric field \( E \) inside the shell is zero, we can substitute this into the equation: \[ 0 = -\frac{dV}{dr} \] - This implies that the rate of change of potential with respect to distance \( r \) is zero, which means the potential \( V \) must be constant throughout the interior of the shell. - **Conclusion**: Statement 1 is also **true**. 4. **Conclusion**: - Both statements are true, and Statement 2 provides the correct explanation for Statement 1. Therefore, the answer is that both statements are true, and Statement 2 justifies Statement 1. ### Final Answer: Both statements are true, and Statement 2 is the correct explanation for Statement 1. ---
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