A cell of emf 16V and internal resistant `4 Omega ` can deliver maximum power to a load of resistance R where R is equal to

Options

A. `2Omega`
B. `16 Omega`
C. `4 Omega`
D. `8 Omega`

Answer

To solve the problem of finding the load resistance \( R \) that allows a cell with an EMF of 16V and an internal resistance of 4Ω to deliver maximum power, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Maximum Power Transfer Theorem**:
According to the maximum power transfer theorem, maximum power is delivered to the load when the load resistance \( R \) is equal to the internal resistance \( r \) of the source.

\[ R = r \]

2. **Identify the Internal Resistance**:
From the problem, we know the internal resistance \( r \) of the cell is 4Ω.

3. **Apply the Maximum Power Condition**:
Since we need to find the load resistance \( R \) for maximum power transfer, we set:

\[ R = r = 4Ω \]

4. **Conclusion**:
Therefore, the load resistance \( R \) that allows the cell to deliver maximum power is:

\[ R = 4Ω \]

### Final Answer:
The value of the load resistance \( R \) is **4Ω**.

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