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A wire of resistance R is cut into ‘ n ’...

A wire of resistance R is cut into ‘ n ’ equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be

A

`( r )/(n )`

B

`( r )/( n^(2))`

C

`rn `

D

`n^(2) r `

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The correct Answer is:
To find the equivalent resistance of a wire of resistance \( R \) that is cut into \( n \) equal parts and connected in parallel, we can follow these steps: ### Step 1: Determine the resistance of each part When the wire of resistance \( R \) is cut into \( n \) equal parts, the resistance of each part can be calculated as: \[ R_{\text{each}} = \frac{R}{n} \] ### Step 2: Set up the formula for equivalent resistance in parallel For resistors connected in parallel, the formula for equivalent resistance \( R_{\text{eq}} \) is given by: \[ \frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n} \] Since all \( n \) resistances are equal (each is \( R_{\text{each}} = \frac{R}{n} \)), we can rewrite the equation as: \[ \frac{1}{R_{\text{eq}}} = n \cdot \frac{1}{R_{\text{each}}} \] ### Step 3: Substitute the value of \( R_{\text{each}} \) Substituting \( R_{\text{each}} = \frac{R}{n} \) into the equation, we have: \[ \frac{1}{R_{\text{eq}}} = n \cdot \frac{1}{\frac{R}{n}} = n \cdot \frac{n}{R} = \frac{n^2}{R} \] ### Step 4: Solve for \( R_{\text{eq}} \) Now, taking the reciprocal to find \( R_{\text{eq}} \): \[ R_{\text{eq}} = \frac{R}{n^2} \] ### Final Answer Thus, the equivalent resistance of the combination is: \[ R_{\text{eq}} = \frac{R}{n^2} \] ---
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