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Figure shows the circuit of a flashing l...

Figure shows the circuit of a flashing lamp, used at construction sites. The fluorescent lamp L, having negligible capacitance, is connected in parallel across the capacitor C of an RC circuit . There is a current through the lamp only when the potential difference across it reaches the breakdown voltage `V_L)`. In this event, the capacitor discharges completley through the lamp and lamp flashes momentarily.

Consider an instant, when the capacitor has just discharged through the flash light. Taking this instant as t=0, the time after which the lamp flashes momentarily is given by

A

`T_(0) =RCln ((epsilon)/(epsilon-V_(L)))`

B

`T_(0) =RC[1-ln ((epsilon)/(V_(L)))]`

C

`T_(0)= RC ln ((epsilon)/(V_(L)))`

D

`T_(0)=RC ln ((epsilon-V_(L))/(epsilon))`

Text Solution

Verified by Experts

The correct Answer is:
A
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Figure shows the circuit of a flashing lamp, used at construction sites. The fluorescent lamp L, having negligible capacitance, is connected in parallel across the capacitor C of an RC circuit . There is a current through the lamp only when the potential difference across it reaches the breakdown voltage V_1) . In this event, the capacitor discharges completley through the lamp and lamp flashes momentarily. Which of the following graphs represents the variation fo potential drop across the resistor ?

Figure shows the circuit of a flashing lamp, used at construction sites. The fluorescent lamp L, having negligible capacitance, is connected in parallel across the capacitor C of an RC circuit . There is a current through the lamp only when the potential difference across it reaches the breakdown voltage V_1) . In this event, the capacitor discharges completley through the lamp and lamp flashes momentarily. The number of flashes per second produced by the arrangement is ( neglecting th etime of flashing or discharging of capacitor)

Knowledge Check

  • A capacitor or capacitance C_(1) is charge to a potential V and then connected in parallel to an uncharged capacitor of capacitance C_(2) . The fianl potential difference across each capacitor will be

    A
    `(C_(1)V)/(C_(1)+C_(2))`
    B
    `(C_(2)V)/(C_(1)+C_(2))`
    C
    `1+(C_(2))/(C_(1))`
    D
    `1-(C_(2))/(C_(1))`

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