The number of glycosidic bonds associated with DNA of diploid human cell are

Options

A. `6.6xx 10^(9)`
B. `2xx 6.6x 10^(9)`
C. `3.3 xx 10^(9)`
D. `3.3 xx 10^(9) - 2`

Answer

To determine the number of glycosidic bonds associated with the DNA of a diploid human cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of DNA**:
- DNA is composed of nucleotides, which consist of a phosphate group, a sugar (deoxyribose), and a nitrogenous base (adenine, thymine, cytosine, or guanine).
- Each nucleotide is linked to another nucleotide through a phosphodiester bond between the phosphate group of one nucleotide and the sugar of the next.

2. **Identify the Glycosidic Bond**:
- The glycosidic bond in DNA is formed between the sugar molecule (deoxyribose) and the nitrogenous base. Specifically, it connects the 1' carbon of the sugar to the nitrogen atom of the base.
- Each nucleotide has one glycosidic bond.

3. **Calculate the Total Number of Nucleotides in a Diploid Human Cell**:
- The diploid human genome contains approximately 6.6 billion base pairs (6.6 x 10^9 base pairs).
- Since each base pair consists of two nucleotides (one from each strand of DNA), the total number of nucleotides is 2 x 6.6 x 10^9.

4. **Calculate the Total Number of Glycosidic Bonds**:
- Since each nucleotide has one glycosidic bond, the total number of glycosidic bonds in the diploid human genome is equal to the total number of nucleotides.
- Therefore, the total number of glycosidic bonds = 2 x 6.6 x 10^9 = 1.32 x 10^10.

5. **Final Answer**:
- The total number of glycosidic bonds associated with the DNA of a diploid human cell is **1.32 x 10^10**.