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A drop of olive oil of radius 0.25 mm sp...

A drop of olive oil of radius 0.25 mm spreads into a circular film of radius 5 cm on the water surface. Estimate the molecular size of the olive oil

Text Solution

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Area of the film, `A=pir^(2)cm^(2)`
= `25picm^(2)" "[because"Radius of the film",r=5cm]`
Volume of the drop, `V=4/3pi("Radius of oil drop")^(3)`
= `4/3xxpixx(0.25mm)^(3)`
= `4/3xxpixx(2.5xx10^(-1))^(3)mm^(3)`
= `4/3xxpixx15.6xx10^(-3)mm^(3)`
= `4/3xxpixx15.6xx10^(-6)cm^(3)`
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