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The speed of a sound wave depends on its...

The speed of a sound wave depends on its wavelength `lamda`, and frequency v. Find an expression for the spped of sound.

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To find the expression for the speed of sound in terms of its wavelength (λ) and frequency (μ), we can follow these steps: ### Step-by-Step Solution: 1. **Define the Variables**: - Let the speed of sound be denoted as \( v \). - Let the wavelength be denoted as \( \lambda \). - Let the frequency be denoted as \( \mu \). 2. **Establish the Relationship**: - According to the problem, the speed of sound depends on its wavelength and frequency. We can express this relationship as: \[ v \propto \lambda^A \mu^B \] - Here, \( A \) and \( B \) are constants that we need to determine. 3. **Introduce a Constant of Proportionality**: - To eliminate the proportionality, we introduce a constant \( K \): \[ v = K \lambda^A \mu^B \] 4. **Dimensional Analysis**: - We need to analyze the dimensions of each term: - The dimension of speed \( v \) is \( [L T^{-1}] \). - The dimension of wavelength \( \lambda \) is \( [L] \). - The dimension of frequency \( \mu \) is \( [T^{-1}] \). 5. **Write the Dimensional Equation**: - Substituting the dimensions into the equation gives us: \[ [L T^{-1}] = [L^A] [T^{-B}] \] - This can be rewritten as: \[ L^1 T^{-1} = L^A T^{-B} \] 6. **Equate the Exponents**: - By equating the exponents of \( L \) and \( T \) from both sides, we get two equations: - For \( L \): \( 1 = A \) - For \( T \): \( -1 = -B \) which simplifies to \( B = 1 \) 7. **Substitute the Values of A and B**: - Now that we have \( A = 1 \) and \( B = 1 \), we can substitute these values back into our equation: \[ v = K \lambda^1 \mu^1 \] - This simplifies to: \[ v = K \lambda \mu \] 8. **Final Expression**: - The expression for the speed of sound can be written as: \[ v = K \lambda \mu \] - If we consider \( K \) to be a constant that can be taken as 1 for simplicity in this context, we can express the speed of sound as: \[ v = \lambda \mu \] ### Final Answer: The expression for the speed of sound is: \[ v = \lambda \mu \]
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A transverse sinusoidal wave of amplitude a, wavelength lamda and frequency f is travelling on a stretched string. The maximum speed of any point on the string is v/10, where v is the speed of propagation of the wave. If a = 10^(-3) m and y = 10m/s, then lamda and f are given by

A transverse sinusoidal wave of amplitude A, wavelength lamda and frequency f is travelling along a stretch string. The maximum speed of any point on the string is (v)/(10) , where, V is the velocity of wave propagation. If A=10^(-3)m, and V=10ms^(-1) , then lamda and f are given by