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The length of a uniform rod is 100.0 cm ...

The length of a uniform rod is 100.0 cm and radius is 1.00 cm if length is measured with a meter rod having least count 1mm and radus is measured with vernier callipers having least count 0.1 mm the percentage error in calculated volume of cylinder is

A

`2.1%`

B

0.03

C

`2.01%`

D

`3.2%`

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The correct Answer is:
To solve the problem of calculating the percentage error in the volume of a cylinder given the measurements of length and radius, we will follow these steps: ### Step 1: Identify the given values - Length of the rod (L) = 100.0 cm - Radius of the rod (R) = 1.0 cm - Least count of the meter rod = 1 mm = 0.1 cm - Least count of the Vernier calipers = 0.1 mm = 0.01 cm ### Step 2: Determine the absolute errors - The absolute error in length (ΔL) = Least count of meter rod = 0.1 cm - The absolute error in radius (ΔR) = Least count of Vernier calipers = 0.01 cm ### Step 3: Write the measurements with errors - Length (L) = 100.0 ± 0.1 cm - Radius (R) = 1.0 ± 0.01 cm ### Step 4: Calculate the formula for the volume of a cylinder The volume (V) of a cylinder is given by the formula: \[ V = \pi R^2 L \] ### Step 5: Calculate the relative error in volume The relative error in volume can be calculated using the formula: \[ \frac{\Delta V}{V} = 2 \frac{\Delta R}{R} + \frac{\Delta L}{L} \] ### Step 6: Substitute the values into the relative error formula - Substitute ΔR = 0.01 cm, R = 1.0 cm, ΔL = 0.1 cm, and L = 100.0 cm into the formula: \[ \frac{\Delta V}{V} = 2 \left( \frac{0.01}{1.0} \right) + \left( \frac{0.1}{100.0} \right) \] ### Step 7: Calculate each term - First term: \( 2 \left( \frac{0.01}{1.0} \right) = 0.02 \) - Second term: \( \frac{0.1}{100.0} = 0.001 \) ### Step 8: Add the relative errors \[ \frac{\Delta V}{V} = 0.02 + 0.001 = 0.021 \] ### Step 9: Convert relative error to percentage error To find the percentage error, multiply the relative error by 100: \[ \text{Percentage Error} = 0.021 \times 100 = 2.1\% \] ### Final Answer The percentage error in the calculated volume of the cylinder is **2.1%**. ---
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