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The dimensional formula for moment of co...

The dimensional formula for moment of couple is

A

`[ML^(2)T^(-2)]`

B

`[MLT^(-2)]`

C

`[ML^(-1)T^(-3)]`

D

`[ML^(-2)T^(-2)]`

Text Solution

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The correct Answer is:
To find the dimensional formula for the moment of a couple, we can follow these steps: ### Step 1: Understand the Concept of Moment of Couple The moment of a couple is defined as the product of one of the forces and the perpendicular distance between the two forces. Mathematically, it can be expressed as: \[ \text{Moment of Couple} = F \times d \] where \( F \) is the force and \( d \) is the perpendicular distance between the forces. ### Step 2: Write the Expression for Moment of Couple From the definition, we can write: \[ \text{Moment of Couple} = F \times s \] where \( s \) is the perpendicular distance. ### Step 3: Determine the Dimensional Formula for Force The dimensional formula for force \( F \) is derived from Newton's second law, which states that force equals mass times acceleration: \[ F = m \cdot a \] The dimensional formula for mass \( m \) is \( [M] \) and for acceleration \( a \) (which is velocity per time) is: \[ a = \frac{L}{T^2} \] Thus, the dimensional formula for force becomes: \[ [F] = [M][L][T^{-2}] = [M L T^{-2}] \] ### Step 4: Determine the Dimensional Formula for Distance The dimensional formula for distance \( s \) is simply: \[ [s] = [L] \] ### Step 5: Combine the Dimensional Formulas Now, substituting the dimensional formulas for force and distance into the expression for the moment of couple: \[ [\text{Moment of Couple}] = [F] \times [s] = [M L T^{-2}] \times [L] \] This simplifies to: \[ [\text{Moment of Couple}] = [M L^2 T^{-2}] \] ### Step 6: Conclusion Thus, the dimensional formula for the moment of a couple is: \[ [M L^2 T^{-2}] \]
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