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The potential energy of a particle varie...

The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.

A

`[ML^(7//2)T^(-2)]`

B

`[ML^(11//2)T^(-2)]`

C

`[M^(2)L^(9//2)T^(-2)]`

D

`[ML^(13//2)T^(-3)]`

Text Solution

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The correct Answer is:
B
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