Home
Class 12
PHYSICS
The radius of a sphere is (2.6 pm 0.1) c...

The radius of a sphere is (2.6 `pm` 0.1) cm The percentage error u iis volume is

A

`0.1/2.6xx100%`

B

`3xx0.1/2.6xx100%`

C

`0.1/(3xx2.6)xx100%`

D

`0.1/2.6%`

Text Solution

AI Generated Solution

The correct Answer is:
To find the percentage error in the volume of a sphere given the radius and its uncertainty, we can follow these steps: ### Step 1: Identify the given values The radius \( r \) of the sphere is given as: \[ r = 2.6 \, \text{cm} \] The uncertainty in the radius \( \Delta r \) is: \[ \Delta r = 0.1 \, \text{cm} \] ### Step 2: Write the formula for the volume of a sphere The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] ### Step 3: Determine how the volume depends on the radius The volume \( V \) is directly proportional to \( r^3 \). Thus, the relative error in volume can be expressed in terms of the relative error in radius: \[ \frac{\Delta V}{V} = 3 \frac{\Delta r}{r} \] ### Step 4: Calculate the relative error in radius The relative error in radius is given by: \[ \frac{\Delta r}{r} = \frac{0.1}{2.6} \] ### Step 5: Substitute the relative error into the volume formula Now, substituting this into the volume error formula: \[ \frac{\Delta V}{V} = 3 \left(\frac{0.1}{2.6}\right) \] ### Step 6: Calculate the relative error in volume Calculating the above expression: \[ \frac{\Delta V}{V} = 3 \times \frac{0.1}{2.6} = \frac{0.3}{2.6} \] ### Step 7: Convert to percentage error To find the percentage error, multiply the relative error by 100: \[ \text{Percentage Error} = \left(\frac{0.3}{2.6}\right) \times 100 \] ### Step 8: Perform the final calculation Calculating this gives: \[ \text{Percentage Error} \approx \left(0.1153846\right) \times 100 \approx 11.54\% \] ### Final Result The percentage error in the volume of the sphere is approximately: \[ 11.54\% \]
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - B)|31 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - C)|31 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|20 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -D) (Assertion - Reason Type Questions)|10 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J (Aakash Challengers question))|1 Videos

Similar Questions

Explore conceptually related problems

The radius of a sphere is (4.8 +- 0.1) cm The perecentage error in its volume is

The radius of a sphere is (5.3 +- 0.1) cm The perecentage error in its volume is

The radius of a sphere is (4.5+-0.2)cm . What is the percentage error in volume?

If the percentage error in the radius of a sphere is a , find the percentage error in its volume.

If the percentage error in the radius of a sphere is alpha , find the percentage error in its volume.

The error in the measurement of radius of a sphere is 0.4%. The percentage error in its volume is

The radius of a ball is (5.2pm0.2) cm. The percentage error in the volume of the ball is (approximately).

The percentage error in the measurement of the radius of a sphere is 1.5%. What would be the percentage error in the volume of the sphere ?

The percentage error in the measurement of the radius of a sphere is 1.5%. What would be the percentage error in the volume of the sphere ?

The error in the measument of radius of a sphere is 0.4% . The relative error in its volume is

AAKASH INSTITUTE ENGLISH-UNITS AND MEASUREMENTS-ASSIGNMENT (SECTION - A)
  1. The addition of three masses 1.6 g, 7.32 g and 4.238 g. addressed upto...

    Text Solution

    |

  2. The area of a sheet of length 10.2 cm and width 6.8 cm addressed upto ...

    Text Solution

    |

  3. The radius of a sphere is (2.6 pm 0.1) cm The percentage error u iis v...

    Text Solution

    |

  4. The uncertain digit in the measurement of a length reported as 41.68 c...

    Text Solution

    |

  5. We can reduce random errors by

    Text Solution

    |

  6. The number of significant figures in the measured value 0.0204 is

    Text Solution

    |

  7. The number of significant figures in the measured value 26000 is

    Text Solution

    |

  8. The number of significant zeros present in the measured value 0.020040...

    Text Solution

    |

  9. The number of significant figures in the measured value 4.700 m is the...

    Text Solution

    |

  10. If a calculated value 2.7465 g contains only three significant figures...

    Text Solution

    |

  11. An object of mass 4.237 g occupies a volume 1.72 cm^3. The density of ...

    Text Solution

    |

  12. Round off the value 2.845 to three significant figures

    Text Solution

    |

  13. A length 5.997 m rounded off to three significant figures is written a...

    Text Solution

    |

  14. The order of the magnitude of speed of light in SI unit is

    Text Solution

    |

  15. The values of a number of quantities are used in a mathematical formul...

    Text Solution

    |

  16. What are the dimensions of the change in velocity ?

    Text Solution

    |

  17. The dimensional formula for energy is

    Text Solution

    |

  18. The pair of the quantities having same dimensions is

    Text Solution

    |

  19. The dimensional formula for relative refractive index is

    Text Solution

    |

  20. The dimensional formula [ML^(-1)T^(-2)] is for the quantity

    Text Solution

    |