Home
Class 12
PHYSICS
The dimensionally correct expression for...

The dimensionally correct expression for the resistance R among the following is [P= electric power, l= Electric current 1 = time, V = voltage and E=electric energy]

A

`R=sqrt(Pl)`

B

`R=E/(l^(2)t)`

C

`R=V^(2)P`

D

R = Vl

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - B)|31 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - C)|31 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|20 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -D) (Assertion - Reason Type Questions)|10 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J (Aakash Challengers question))|1 Videos

Similar Questions

Explore conceptually related problems

The dimensionally correct expression for the resistance R among the following is [P = electric power, l = electric current, t = time, V = volatge and E = electric energy]

Which of the following is // are correct about electric current ?

Write an expression for calculating electrical power in terms of current and resistance

Write an expression for calculating electrical power in terms of current and resistance.

Write an expression for the electrical energy spent in the flow of current through an electrical appliances in terms of I, R and t.

When a current I flows through a resistance R for time t, the electrical energy spent is :

Write an expression for the electrical power spent in flow of current through a conductor in terms of resistance and potential difference

Obtain the expression for the torque vec(tau) experienced by an electric dipole of dipole moment vec(p) in a uniform electric field , vec(E )

Statements given below are incorrect. Write the correct statements. Q. When an electric current flows through an electric bulb, the electric energy first changes to light energy and then to heat energy.

The dimension of 1//CR is, where C is capacitance and R is electrical resistance :

AAKASH INSTITUTE ENGLISH-UNITS AND MEASUREMENTS-ASSIGNMENT (SECTION - A)
  1. An object of mass 4.237 g occupies a volume 1.72 cm^3. The density of ...

    Text Solution

    |

  2. Round off the value 2.845 to three significant figures

    Text Solution

    |

  3. A length 5.997 m rounded off to three significant figures is written a...

    Text Solution

    |

  4. The order of the magnitude of speed of light in SI unit is

    Text Solution

    |

  5. The values of a number of quantities are used in a mathematical formul...

    Text Solution

    |

  6. What are the dimensions of the change in velocity ?

    Text Solution

    |

  7. The dimensional formula for energy is

    Text Solution

    |

  8. The pair of the quantities having same dimensions is

    Text Solution

    |

  9. The dimensional formula for relative refractive index is

    Text Solution

    |

  10. The dimensional formula [ML^(-1)T^(-2)] is for the quantity

    Text Solution

    |

  11. The buoyant force F acting on a body depends on the density of medium ...

    Text Solution

    |

  12. The dimensionally correct expression for the resistance R among the fo...

    Text Solution

    |

  13. Which of the following does not have dimensions of force?

    Text Solution

    |

  14. The potential energy of a particle varies with distance x from a fixed...

    Text Solution

    |

  15. The time dependence of a physical quantity P is given by P = P(0)e^(-a...

    Text Solution

    |

  16. The dimensions of potential energy of an object in mass, length and ti...

    Text Solution

    |

  17. Which of the following is a dimensional constant?

    Text Solution

    |

  18. Dimension of solar constant is:

    Text Solution

    |

  19. The amount of heat energy Q, used to heat up a substance depends on it...

    Text Solution

    |

  20. The power of lens is P=1/(f) where f is focal length of the lens. The ...

    Text Solution

    |