If a car, initially at rest, accelerates uniformly to a speed of `50ms^-1` in `25s`, distance travelled by it is

If a car at rest, accelerates uniformly to a speed of 144 km//h in 20s , it covers a distance of

A car starts from rest and accelerates uniformly to a speed of 180 kmh^(-1) in 10 s. The distance covered by the car in the time interval is

A car starting from rest accelerates uniformly to acquire a speed 20 km h^(-1) in 30 min. The distance travelled by car in this time interval will be :

A particle starts with an initial velocity 2.5 m/s along the positive x direction and it accelerates uniformly at the rate 0.50 m/s^2 . A. Find the distance travelled by it in the first two seconds. b.How much time does it take to reach the velocity 7.5 m/s ? c. How much distance will it cover in reaching the velocity 7.5 m/s?

A particle starts with an initial velocity 2.5 m//s along the posiive x-direction and it accelerates uniformly at the rate 0.50 m//s^2. (a) Find the distance travelled by it in the first two seconds (b) How much time does it take to reach the velocity 7.5 m//s ? (c) How much distance will it cover in reaching the velocity 7.5 m//s ?

A particle initially at rest, moves with an acceleration 5 m s^(-2) for 5 s. Find the distance travelled in (a) 4 s, (b) 5 s and (c) 5th second.

A car travels for 20 min with a constant speed of 54 km h^(-1) Find the distance travelled by the car.

Initially a body is at rest. If its acceleration is 5ms^(-2) then the distance travelled in the 18^(th) second is :-

A body starting from rest has an acceleration of 4ms^(-2) . Calculate distance travelled by it in 5th second.