A block of mass 8 kg is sliding on a surface inclined at an angle of `45^(@)` with the horizontal. Calculate the acceleration of the block. The coefficient of friction between the block and surface is 0.6. (Take `g=10m//s^(2)`)

Explanation

To solve the problem, we need to analyze the forces acting on the block and apply Newton's second law of motion. Here’s a step-by-step solution:

### Step 1: Identify the forces acting on the block
The block of mass \( m = 8 \, \text{kg} \) is on an inclined plane at an angle \( \theta = 45^\circ \). The forces acting on the block are:
1. The gravitational force \( \vec{F}_g = m \vec{g} \) acting downwards.
2. The normal force \( \vec{N} \) acting perpendicular to the inclined surface.
3. The frictional force \( \vec{F}_{\text{friction}} \) acting up the incline.

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