A block of mass 10 kg, moving with accel...

A block of mass 10 kg, moving with acceleration `2m//s^(2)` on horizontal rough surface is shown in figure

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A block of mass 10 kg is moving on a rough horizontal surface as shown in figure. At t=0 , velocity of block is 10 m/s towards left and a constant force F= 10 N acts horizontally towards right. Acceleration of the block at t=3s is ( g= 10 m s^(-2) )

A block of mass sqrt(3)//10kg is placed on a rough horizontal surface as shown in the figure. A force of 1N is applied at one end of the block and the block remains stationary. The normal force exerted by the sruface on the block acts(g=10 m//s^(2) )

A block of mass 10 kg is placed on a horizontal surface as shown in the figure and a force F = 100 N is applied on the block as shown, in the figure. The block is at rest with respect to ground. If the contact force between block and ground is 25n (in Newton) then value of n is : (Take g = 10 m//s^(2))

An inclined plane is moving with Constant velocity v = 4 m//s on a horizoontal surface as shown in figure. If a block of mass 2 kg is kept at top of the incline and their is no friction between the block and the incline, then the distance travelled by the incline till the block reaches bottom of the inclined is (g = 10 m//s^(2))

A wedge (inclination theta = 30^(@) from horizontal) is moving with an acceleration a = 4 m//s^(2) vertically up as shown in figure. What is acceleration of block of mass 1 kg w.r.t & reaction by wedge on block respectively. All surface are smooth. Choose correct pair : (g = 10 m//s^(2))

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In the figure shown the man of mass 60kg is lowering a block of mass 10kg with an acceleration of 2m//s^2 . Find the reading of the machine.

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AAKASH INSTITUTE ENGLISH-LAWS OF MOTION-EXERCISE

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