Three forces `vecF_(1)=(2hati+4hatj)N : vecF_(2)=(2hatj-hatk)N` and `vecF_(3)=(hatk-4hati-2hatj)N` are applied on an object of mass 1 kg at rest at origin. The position of the object at t = 2s will be

Three forces vecF_(1)=(3hati+2hatj-hatk) dynes, vecF_(2)=(3hati+4hatj-5hatk) dynes and vecF_(3)=a(hati+hatj-hatk) dynes act simultaneously on a particle. What should be the value of 'a' so that the particle may remain in equilibrium?

The resultant of the forces vecF_(1) = 4hati-3hatj and vecF_(2) = 6hati + 8hatj is

If the resultant of three forces vecF_1 = p hati + 3hatj -hatk, vecF_2 = 6hati-hatk and vecF_3 =-5hati +hatj +2hatk acting on a particle has a magnitude equal to 5 units, then the value of p is

If the resultant of three forces vecF_1= phati +3hatj-hatk , vecF_2 =-5hati+hatj+2hatk and vecF_3= 6hati -hatk acting on a particle has a magnitude equal to 5 units, then what is difference in the values of p ?

If the resultant of three forces vecF_1= phati -3hatj-hatk , vecF_2 =-5hati+hatj+2hatk and vecF_3= 6hati -hatk acting on a particle has a magnitude equal to 5 units, then what is difference in the values of p ?

Three constant forces vecF_1=2hati-3hatj+2hatk , vecF_2=hati+hatj-hatk , and vecF_3=3hati+hatj-2hatk in newtons displace a particle from (1, -1, 2) to (-1, -1, 3) and then to (2, 2, 0) (displacement being measured in meters). Find the total work done by the forces.

The angle between force vecF =(3hati+4hatj-5hatk) unit and displacement vecd = (5hati+4hatj+3hatk) unit is

If veca = 2hati -3hatj-1hatk and vecb =hati + 4hatj -2hatk " then " veca xx vecb is

Three forces given by vectors 2hati + 2hatj. 2hati -2hatj and - 4hatj are acting together on a point object at rest. The object moves along the direction.

Consider two vectors vecF_(1)=2hati+5hatk and vecF_(2)=3hatj+4hatk . The magnitude to thhe scalar product of these vectors is