A torque of 10 Nm is applied on a wheel having angular momentum of `2 kg m^(2)s^(-1)`, calculate the angular momentum of the wheel after 4 seconds.

Explanation

`vec(tau)=(d vec(L))/(dt)`
`vec(tau)=(vec(L)_(2)-vec(L)_(1))/(t)`
`vec(L)_(2)=vec(tau)t+vec(L)_(1)`
`= 10xx4+2`
`= 40+2`
`= 42 kg m^(2)s^(-1)`.