Home
Class 12
PHYSICS
Three point masses of 1kg, 2kg and 3kg l...

Three point masses of `1kg`, `2kg` and `3kg` lie at `(0,0)`, `(1,2)`, `(3,-1)` respectively. Calculate the coordinates of the centre of mass of the system.

Text Solution

AI Generated Solution

To calculate the coordinates of the center of mass of a system of point masses, we can use the following formulas: 1. **Formula for the x-coordinate of the center of mass (X_COM)**: \[ X_{COM} = \frac{M_1 X_1 + M_2 X_2 + M_3 X_3}{M_1 + M_2 + M_3} \] 2. **Formula for the y-coordinate of the center of mass (Y_COM)**: ...
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - J) Aakash Challengers Questions|13 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D (Assertion and reason))|5 Videos
  • TEST 1

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|21 Videos

Similar Questions

Explore conceptually related problems

Two bodies of masses 1 kg and 3 kg are lying in xy plane at (0, 0) and (2, -1) respectively. What are the coordinates of the centre of mass ?

Two bodies of masses 1 kg and 2 kg are located at (1,2) and (-1,3), respectively. Calculate the coordinates of center of mass.

Two bodies of masses 1kg and 2kg are lying in xy plane at (-1,2) and (2,4) respectively. What are the coordinates of the center of mass?

Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2,-1) respectively. What are the coordinates of the centre of mass ? Hint. x_(cm)=(m_(1)x_(1)+m_(2)x_(2))/(m_(1)+x_(2)) , y_(cm)=(m_(1)y_(1)+m_(2)y_(2))/(m_(1)+m_(2))

A system consists of 3 particles each of mass 2 kg located at (1,1), (2,2) and (3, 3) respectively. Find the coordinates of the centre of mass.

Two bodies of masses 0.5 kg and 1 kg are lying in the X-Y plane at points (-1, 2) and (3, 4) respectively. Locate the centre of mass of the system.

Four point masses 1 kg, 1 kg, 2 kg and 2 kg are placed at the corners of a square of side a m as shown in Fig. Find the centre of mass of the system.

Four particles of mass 5,3,2,4 kg are at the points (1,6),(-1,5),(2,-3),(-1,-4) . Find the coordinates of their centre of mass.

Three particles of masses 1.0 kg 2.0 kg and 3.0 kg are placed at the corners A,B and C respectively of an equilateral triangle ABC of edge 1m. Locate the centre of mass of the system.

The coordinates of a triangle ABC are A(1,2) , B(4,6) and C(-3,-2) . Three particles of masses 1kg , 2kg and m kg are placed the vertices of the triangle. If the coordinate of the centre of mass are ((3)/(5),2) , calculate the mass m .

AAKASH INSTITUTE ENGLISH-SYSTEM OF PARTICLES AND ROTATIONAL MOTION-Try Yourself
  1. Three point masses of 1kg, 2kg and 3kg lie at (0,0), (1,2), (3,-1) res...

    Text Solution

    |

  2. Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2...

    Text Solution

    |

  3. Three point masses of 1kg, 2kg and 3kg lie at (0,0), (1,2), (3,-1) res...

    Text Solution

    |

  4. Three particles of masses m,m and 4kg are kept at a verticals of trian...

    Text Solution

    |

  5. Three particles having their masses in the ratio 1 : 3 : 5 are kept at...

    Text Solution

    |

  6. Centre of mass of the system lies inside disc or square plate and why ...

    Text Solution

    |

  7. Two particles of equal mass are moving along the same line with the sa...

    Text Solution

    |

  8. Two particles of equal mass are moving along the same straight line wi...

    Text Solution

    |

  9. A shell following a parabolic path explodes somewhere in its flight. T...

    Text Solution

    |

  10. All the particles are situated at a distance R from the origin. The di...

    Text Solution

    |

  11. Will the velocity and acceleration of centre of mass change if particl...

    Text Solution

    |

  12. vecA=(3hati+2hatj-6hatk) and vecB=(hati-2hatj+hatk), find the scalar p...

    Text Solution

    |

  13. vecA=(hati-2hatj+6hatk) and vecB=(hati-2hatj+hatk), find the cross pro...

    Text Solution

    |

  14. Find a unit vector in the direction of vector vecA=(hati-2hatj+hatk)

    Text Solution

    |

  15. Find a vector perpendicular to vector vecA=(hati+2hatj-3hatk) as well ...

    Text Solution

    |

  16. The angular displacement of a particle is 24 rad in 10 seconds. Calcul...

    Text Solution

    |

  17. The angular velocity of a rigid body is 24 rad s^(-1), Calculate the t...

    Text Solution

    |

  18. The angular velocity of circular disc of radius 2cm is 20 rad s^(-1). ...

    Text Solution

    |

  19. What is the angular velocity of a particle lying on the axis of rotati...

    Text Solution

    |

  20. What is the angular acceleration of a particle moving with constant an...

    Text Solution

    |

  21. A wheel is rotating with an angular velocity of 3 rad s^(-1). If the a...

    Text Solution

    |