Three particles having their masses in the ratio `1 : 3 : 5` are kept at the vertices of a triangle `ABC`. Coordinate of `A`, `B` and `C` are `(9,-3)`, `(3,4)` and `(0,0)`. Find the coordinates of the centre of mass.
Hint. `x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i))`, `y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))`

Explanation

To find the coordinates of the center of mass of the three particles located at the vertices of triangle ABC with given coordinates and masses in the ratio 1:3:5, we can follow these steps:

### Step 1: Assign Masses
Let the masses of the particles be:
- \( m_1 = m \) (at vertex A)
- \( m_2 = 3m \) (at vertex B)
- \( m_3 = 5m \) (at vertex C)

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