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vec(A)=(hat(i)-2hat(j)+6hat(k)) and vec(...

`vec(A)=(hat(i)-2hat(j)+6hat(k))` and `vec(B)=(hat(i)-2hat(j)+hat(k))`, find the cross product between `vec(A)` and `vec(B)`.

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`vec(A)xxvec(B)=|(hat(i),hat(j),hat(k)),(1,-2,6),(1,-2,1)|=hat(i)(-2+12)+hat(j)(6-1)+hat(k)(-2+2)=10hat(i)+5hat(j)`
Hint : `vec(A)xx vec(B) = |(hat(i),hat(j),hat(k)),(A_(x),A_(y),A_(z)),(B_(x),B_(y),B_(z))|`
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