Home
Class 12
PHYSICS
The angular momentum of a particle chang...

The angular momentum of a particle changes from `4kg m^(2)s^(-1)` to `8kg m^(2)s^(-1)` is `2` seconds. Calcualte the torque acting on the particle

Text Solution

AI Generated Solution

To solve the problem of calculating the torque acting on a particle when its angular momentum changes, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the given values**: - Initial angular momentum, \( L_1 = 4 \, \text{kg m}^2/\text{s} \) - Final angular momentum, \( L_2 = 8 \, \text{kg m}^2/\text{s} \) - Time interval, \( \Delta t = 2 \, \text{s} \) ...
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - J) Aakash Challengers Questions|13 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D (Assertion and reason))|5 Videos
  • TEST 1

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|21 Videos

Similar Questions

Explore conceptually related problems

The angular velocity of a particle changes from 100 rad s^(-1) to 200 rad s^(-1) in 4s . Calculate the angular accelertion of the particle ?

The angular velocity of a particle changes from 100 rad s^(-1) to 200 rad s^(-1) in 4s . Calculate the angular accelertion of the particle ?

The uncertainty in the momentum of a particle is 6.0 xx 10^(-2) kg m s^(-1) .Calculate the uncertainty in the position

A particle is moving on a straight line x + y = 2. Its angular momentum about origin is L = 3t + 2 (kg m^2s^(-1) ). Find the force acting on the particle at t = 2 s. (x and y are in metre)

The momentum P ( in kg ms^(-1) ) of a particle is varying with time t ( in second ) as p=2+ 3t^(2) . The force acting on the particle at t=3s will be

The linear momentum of a particle is given by vec(P)=(a sin t hati- acos t hatj) kg- m//s . A force vec(F) is acting on the particle. Select correct alternative/s:

A particle of mass M and radius of gyration K is rotating with angular acceleration alpha . The torque acting on the particle is

The momentum p (in kg ms^(-1) ) of a particle is varying with time t (in second) as p=2+3 t^(2) . The force acting on the particle at t=3s will be

The angular momentum changes from 4 unit to 10 unit in 2 seconds. The torque is

A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are a=(4 hat(i)+3hat(j))m//s^(2) and p=(8 hat(i)-6hat(j))"kg-m/s" . The motion of the particle is

AAKASH INSTITUTE ENGLISH-SYSTEM OF PARTICLES AND ROTATIONAL MOTION-Try Yourself
  1. The angular momentum of a particle changes from 4kg m^(2)s^(-1) to 8kg...

    Text Solution

    |

  2. Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2...

    Text Solution

    |

  3. Three point masses of 1kg, 2kg and 3kg lie at (0,0), (1,2), (3,-1) res...

    Text Solution

    |

  4. Three particles of masses m,m and 4kg are kept at a verticals of trian...

    Text Solution

    |

  5. Three particles having their masses in the ratio 1 : 3 : 5 are kept at...

    Text Solution

    |

  6. Centre of mass of the system lies inside disc or square plate and why ...

    Text Solution

    |

  7. Two particles of equal mass are moving along the same line with the sa...

    Text Solution

    |

  8. Two particles of equal mass are moving along the same straight line wi...

    Text Solution

    |

  9. A shell following a parabolic path explodes somewhere in its flight. T...

    Text Solution

    |

  10. All the particles are situated at a distance R from the origin. The di...

    Text Solution

    |

  11. Will the velocity and acceleration of centre of mass change if particl...

    Text Solution

    |

  12. vecA=(3hati+2hatj-6hatk) and vecB=(hati-2hatj+hatk), find the scalar p...

    Text Solution

    |

  13. vecA=(hati-2hatj+6hatk) and vecB=(hati-2hatj+hatk), find the cross pro...

    Text Solution

    |

  14. Find a unit vector in the direction of vector vecA=(hati-2hatj+hatk)

    Text Solution

    |

  15. Find a vector perpendicular to vector vecA=(hati+2hatj-3hatk) as well ...

    Text Solution

    |

  16. The angular displacement of a particle is 24 rad in 10 seconds. Calcul...

    Text Solution

    |

  17. The angular velocity of a rigid body is 24 rad s^(-1), Calculate the t...

    Text Solution

    |

  18. The angular velocity of circular disc of radius 2cm is 20 rad s^(-1). ...

    Text Solution

    |

  19. What is the angular velocity of a particle lying on the axis of rotati...

    Text Solution

    |

  20. What is the angular acceleration of a particle moving with constant an...

    Text Solution

    |

  21. A wheel is rotating with an angular velocity of 3 rad s^(-1). If the a...

    Text Solution

    |