The moment of inerta of a ring of mass `1kg` about an axis passing through its centre perpendicular to its surface is `4kgm^(2)`. Calculate the radius of the ring.

Explanation

To solve the problem, we need to calculate the radius of a ring given its mass and moment of inertia. Here are the steps to find the solution:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Mass of the ring, \( m = 1 \, \text{kg} \)
- Moment of inertia of the ring, \( I = 4 \, \text{kg m}^2 \)

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