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Two solid spheres of different mass, rad...

Two solid spheres of different mass, radii and denisty roll down a rough inclined plane under indentical situation. Their time to come down is independent o their :-

A

Mass

B

Radius

C

Density

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of two solid spheres rolling down a rough inclined plane. The goal is to determine which factors the time taken to roll down the incline is independent of. ### Step-by-Step Solution: 1. **Identify the Parameters**: - Let the mass of the first sphere be \( m_1 \), its radius \( r_1 \), and its density \( \rho_1 \). - Let the mass of the second sphere be \( m_2 \), its radius \( r_2 \), and its density \( \rho_2 \). - The angle of inclination of the plane is \( \theta \) and the height of the incline is \( h \). 2. **Determine the Acceleration**: - The acceleration \( a \) of a rolling sphere down the incline can be expressed as: \[ a = \frac{g \sin \theta}{1 + \frac{I}{m r^2}} \] - Here, \( I \) is the moment of inertia of the sphere. For a solid sphere, \( I = \frac{2}{5} m r^2 \). 3. **Substituting the Moment of Inertia**: - Substitute the moment of inertia into the acceleration formula: \[ a = \frac{g \sin \theta}{1 + \frac{\frac{2}{5} m r^2}{m r^2}} = \frac{g \sin \theta}{1 + \frac{2}{5}} = \frac{g \sin \theta}{\frac{7}{5}} = \frac{5g \sin \theta}{7} \] 4. **Calculate the Distance**: - The distance \( s \) that the sphere rolls down the incline can be related to the height \( h \) and the angle \( \theta \): \[ s = \frac{h}{\sin \theta} \] 5. **Using Kinematic Equation to Find Time**: - The time \( t \) taken to roll down the incline can be derived from the equation of motion: \[ s = ut + \frac{1}{2} a t^2 \] - Since the initial velocity \( u = 0 \), we simplify to: \[ s = \frac{1}{2} a t^2 \implies t^2 = \frac{2s}{a} \implies t = \sqrt{\frac{2s}{a}} \] 6. **Substituting for Time**: - Substitute \( s \) and \( a \) into the time equation: \[ t = \sqrt{\frac{2 \cdot \frac{h}{\sin \theta}}{\frac{5g \sin \theta}{7}}} = \sqrt{\frac{14h}{5g \sin^2 \theta}} \] 7. **Independence of Mass, Radius, and Density**: - Notice that the final expression for time \( t \) does not contain \( m \), \( r \), or \( \rho \). This indicates that the time taken to roll down the incline is independent of the mass, radius, and density of the spheres. ### Conclusion: Therefore, the time taken for the spheres to roll down the inclined plane is independent of their mass, radius, and density.
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