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A man of mass 60 kg is standing on a boa...

A man of mass 60 kg is standing on a boat of mass 140 kg, which is at rest in still water. The man is initially at 20 m from the shore. He starts walking on the boat for 4 s with constant speed 1.5 m/s towards the shore. The final distance of the man from the shore is

A

15.8 m

B

4.2 m

C

12.6 m

D

14.1 m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the situation using the principles of conservation of momentum and relative motion. ### Step 1: Understand the Initial Conditions - The man has a mass of 60 kg and is standing on a boat with a mass of 140 kg. - Initially, both the man and the boat are at rest, and the man is 20 m away from the shore. ### Step 2: Calculate the Distance the Man Walks - The man walks towards the shore with a constant speed of 1.5 m/s for a duration of 4 seconds. - The distance \( S \) that the man covers while walking can be calculated using the formula: \[ S = \text{speed} \times \text{time} = 1.5 \, \text{m/s} \times 4 \, \text{s} = 6 \, \text{m} \] ### Step 3: Determine the Movement of the Boat - As the man walks towards the shore, the boat will move in the opposite direction to conserve the center of mass of the system (man + boat). - The total mass of the system is \( 60 \, \text{kg} + 140 \, \text{kg} = 200 \, \text{kg} \). - Using the conservation of momentum: \[ \text{Initial momentum} = \text{Final momentum} \] Initially, the momentum is zero since both are at rest. After the man starts walking: \[ 60 \, \text{kg} \times 1.5 \, \text{m/s} = (60 \, \text{kg} + 140 \, \text{kg}) \times U \] Where \( U \) is the speed of the boat in the opposite direction. ### Step 4: Solve for the Speed of the Boat - The momentum equation becomes: \[ 90 \, \text{kg m/s} = 200 \, \text{kg} \times U \] Solving for \( U \): \[ U = \frac{90}{200} = 0.45 \, \text{m/s} \] ### Step 5: Calculate the Distance the Boat Moves - The boat moves for the same duration of 4 seconds: \[ \text{Distance covered by the boat} = U \times \text{time} = 0.45 \, \text{m/s} \times 4 \, \text{s} = 1.8 \, \text{m} \] ### Step 6: Calculate the Final Distance from the Shore - The final distance \( Y \) of the man from the shore can be calculated as: \[ Y = \text{Initial distance} - \text{Distance covered by the man} + \text{Distance covered by the boat} \] Substituting the values: \[ Y = 20 \, \text{m} - 6 \, \text{m} + 1.8 \, \text{m} = 15.8 \, \text{m} \] ### Final Answer The final distance of the man from the shore is **15.8 meters**.
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