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Point masses m(1) and m(2) are placed at...

Point masses `m_(1) and m_(2)` are placed at the opposite ends of a rigid rod of length `L`, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point `P` on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity `omega_(0)` is minimum, is given by :

A

`x=(m_(2)L)/(m_(1)+m_(2))`

B

`x=(m_(1)L)/(m_(1)+m_(2))`

C

`x=(m_(1))/(m_(2))L`

D

`x=(m_(2))/(m_(1))L`

Text Solution

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The correct Answer is:
A
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