Home
Class 12
PHYSICS
The instantaneous angular position of a ...

The instantaneous angular position of a point on a rotating wheel is given by the equation `Q(t) =2t^(3)-6t^(2)`. The torque on the wheel becomes zero at

A

t = 2 s

B

t = 1 s

C

t = 0.5 s

D

t = 0.25 s

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The instantaneous angular position of a point on a rotating wheel is given by the equation theta(t) = 2t^(3) - 6 t^(2) The torque on the wheel becomes zero at

The instantaneous angular position of a point on a rotating wheel is given by the equation theta(t) = 2t^(3) - 6 t^(2) The torque on the wheel becomes zero at a) t = 1 s b) t = 0.5 s c) t = 0.25 s d) t = 2 s

The angular position of a point over a rotating flywheel is changing according to the relation, theta = (2t^3 - 3t^2 - 4t - 5) radian. The angular acceleration of the flywheel at time, t = 1 s is

A angular positio of a point on the rim of a rotating wheel is given by theta=4t-3t^(2)+t^(3) where theta is in radiuans and t is in seconds. What are the angualr velocities at (a). t=2.0 and (b). t=4.0s (c). What is the average angular acceleration for the time interval that begins at t=2.0s and ends at t=4.0s ? (d). What are the instantaneous angular acceleration at the biginning and the end of this time interval?

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

A boat of mass 300 kg moves according to the equation x= 1.2t^(2) - 0.2 t^(3) . When the force will become zero ?

The variation of angular position theta , of a point on a rotating rigid body, with time t is shown in Fig. Is the body rotating clock wise or anti-clockwise ?

The distances moved by a particle in time t seconds is given by s=t^(3)-6t^(2)-15t+12 . The velocity of the particle when acceleration becomes zero, is

The displacement of a particle moving along the x-axis is given by equation x=2t^(3)-21"t"^(2)+60t+6 .The possible acceleration of the particle when its velocity is zero is