Home
Class 12
PHYSICS
The ratio of radii of gyration of a circ...

The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius about an axis passing through their centres and perpendicular to their planes are

A

`sqrt(2):1`

B

`1:sqrt(2)`

C

`3:2`

D

`2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the radii of gyration of a circular ring and a circular disc of the same mass and radius about an axis passing through their centers and perpendicular to their planes, we can follow these steps: ### Step 1: Understand the Concept of Radius of Gyration The radius of gyration \( k \) is defined as the distance from the axis of rotation at which the total mass of the body can be assumed to be concentrated, such that the moment of inertia remains the same. ### Step 2: Moment of Inertia for the Circular Ring For a circular ring of mass \( m \) and radius \( r \), the moment of inertia \( I \) about an axis passing through its center and perpendicular to its plane is given by: \[ I_{\text{ring}} = m r^2 \] ### Step 3: Moment of Inertia for the Circular Disc For a circular disc of the same mass \( m \) and radius \( r \), the moment of inertia \( I \) about an axis passing through its center and perpendicular to its plane is given by: \[ I_{\text{disc}} = \frac{1}{2} m r^2 \] ### Step 4: Relate Moment of Inertia to Radius of Gyration The moment of inertia can also be expressed in terms of the radius of gyration \( k \): \[ I = m k^2 \] From this, we can find the radius of gyration for both the ring and the disc. ### Step 5: Calculate Radius of Gyration for the Ring Using the moment of inertia for the ring: \[ m k_r^2 = m r^2 \implies k_r^2 = r^2 \implies k_r = r \] ### Step 6: Calculate Radius of Gyration for the Disc Using the moment of inertia for the disc: \[ m k_d^2 = \frac{1}{2} m r^2 \implies k_d^2 = \frac{1}{2} r^2 \implies k_d = \frac{r}{\sqrt{2}} \] ### Step 7: Find the Ratio of the Radii of Gyration Now we can find the ratio of the radii of gyration \( k_r \) and \( k_d \): \[ \text{Ratio} = \frac{k_r}{k_d} = \frac{r}{\frac{r}{\sqrt{2}}} = \sqrt{2} \] ### Step 8: Final Answer Thus, the ratio of the radii of gyration of a circular ring and a circular disc of the same mass and radius about an axis passing through their centers and perpendicular to their planes is: \[ \sqrt{2} : 1 \]
Promotional Banner

Similar Questions

Explore conceptually related problems

Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is

If a circular concentric hole is made on a disc then about an axis passing through the centre of the disc and perpendicular to its plane

The ratio of the radii of gyration of a circular disc to that of a circular ring, each of same mass and radius, around their respective axes is.

The ratio of the radii of gyration of a spherical shell and solid sphere of the same mass and radius about a tangential axis is

The ratio of the radii of gyration of a spherical shell and solid sphere of the same mass and radius about a tangential axis is

A metallic circular disc having a circular hole at its centre rotates about an axis passing through its centre and perpendicular to its plane. When the disc is heated:

A metallic circular disc having a circular hole at its centre rotates about an axis passing through its centre and perpendicular to its plane. When the disc is heated:

The ratio of the radii of gyration of a circular disc and a circular ring of the same radii about a tangential axis perpendicular to plane of disc or ring is

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

Radius of gyration of a uniform circular disc about an axis passing through its centre of gravity and perpendicular to its plane is