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A large disc has mass 2kg and radius 0.2...

A large disc has mass 2kg and radius 0.2 m and initial angular velocity 50 rad/s and small disc has mass 4kg and radius 0.1 m and initial angular velocity 200 rad/s both rotating about their common axis. Then the common final angular velocity after discs are in contact is,

A

40

B

60

C

100

D

120

Text Solution

AI Generated Solution

The correct Answer is:
To find the common final angular velocity after the two discs are in contact, we can use the principle of conservation of angular momentum. Here’s a step-by-step solution: ### Step 1: Identify the given values - Mass of the large disc, \( m_1 = 2 \, \text{kg} \) - Radius of the large disc, \( r_1 = 0.2 \, \text{m} \) - Initial angular velocity of the large disc, \( \omega_1 = 50 \, \text{rad/s} \) - Mass of the small disc, \( m_2 = 4 \, \text{kg} \) - Radius of the small disc, \( r_2 = 0.1 \, \text{m} \) - Initial angular velocity of the small disc, \( \omega_2 = 200 \, \text{rad/s} \) ### Step 2: Calculate the moment of inertia for both discs The moment of inertia \( I \) for a disc rotating about its central axis is given by the formula: \[ I = \frac{1}{2} m r^2 \] **For the small disc:** \[ I_2 = \frac{1}{2} m_2 r_2^2 = \frac{1}{2} \times 4 \times (0.1)^2 = \frac{1}{2} \times 4 \times 0.01 = 0.02 \, \text{kg m}^2 \] **For the large disc:** \[ I_1 = \frac{1}{2} m_1 r_1^2 = \frac{1}{2} \times 2 \times (0.2)^2 = \frac{1}{2} \times 2 \times 0.04 = 0.04 \, \text{kg m}^2 \] ### Step 3: Calculate the initial angular momentum of both discs The initial angular momentum \( L \) is given by: \[ L = I \omega \] **For the small disc:** \[ L_2 = I_2 \omega_2 = 0.02 \times 200 = 4 \, \text{kg m}^2/\text{s} \] **For the large disc:** \[ L_1 = I_1 \omega_1 = 0.04 \times 50 = 2 \, \text{kg m}^2/\text{s} \] ### Step 4: Calculate the total initial angular momentum \[ L_{\text{initial}} = L_1 + L_2 = 2 + 4 = 6 \, \text{kg m}^2/\text{s} \] ### Step 5: Calculate the total moment of inertia after the discs are in contact \[ I_{\text{total}} = I_1 + I_2 = 0.04 + 0.02 = 0.06 \, \text{kg m}^2 \] ### Step 6: Apply conservation of angular momentum According to the conservation of angular momentum: \[ L_{\text{initial}} = L_{\text{final}} \] \[ L_{\text{final}} = I_{\text{total}} \omega_f \] Thus, \[ 6 = 0.06 \omega_f \] ### Step 7: Solve for the final angular velocity \( \omega_f \) \[ \omega_f = \frac{6}{0.06} = 100 \, \text{rad/s} \] ### Final Answer The common final angular velocity after the discs are in contact is \( \omega_f = 100 \, \text{rad/s} \). ---
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