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A : For an object in rolling motion rota...

A : For an object in rolling motion rotational kinetic energy is always equal to translational kinetic energy.
R : For an object in rolling motion magnitude of linear speed and angular speed are equal.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion,

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion,

C

If Assertion is true statement but Reason is false,

D

If both Assertion and Reason are false statements,

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reason question, we need to analyze both statements carefully. ### Step-by-Step Solution: 1. **Understanding Rolling Motion**: - Rolling motion is a combination of translational motion (movement of the center of mass) and rotational motion (spinning around an axis). - The total kinetic energy of a rolling object is the sum of its translational kinetic energy and rotational kinetic energy. 2. **Kinetic Energy Formulas**: - The translational kinetic energy (KE_trans) is given by the formula: \[ KE_{\text{trans}} = \frac{1}{2} mv^2 \] - The rotational kinetic energy (KE_rot) is given by the formula: \[ KE_{\text{rot}} = \frac{1}{2} I \omega^2 \] - Here, \(m\) is the mass, \(v\) is the linear speed, \(I\) is the moment of inertia, and \(\omega\) is the angular speed. 3. **Relating Linear Speed and Angular Speed**: - For a rolling object, the relationship between linear speed \(v\) and angular speed \(\omega\) is given by: \[ v = r \omega \] - This means that the linear speed is not equal to the angular speed; they are related through the radius \(r\) of the object. 4. **Moment of Inertia**: - The moment of inertia \(I\) depends on the shape of the object. For example: - For a solid disk, \(I = \frac{1}{2} m r^2\) - For a hollow ring, \(I = m r^2\) 5. **Total Kinetic Energy in Rolling Motion**: - The total kinetic energy of a rolling object can be expressed as: \[ KE_{\text{rolling}} = KE_{\text{trans}} + KE_{\text{rot}} = \frac{1}{2} mv^2 + \frac{1}{2} I \omega^2 \] - Substituting \(I\) and \(\omega\) into this equation shows that the translational and rotational kinetic energies are not necessarily equal. 6. **Evaluating the Assertion (A)**: - The assertion states that "for an object in rolling motion, rotational kinetic energy is always equal to translational kinetic energy." This is **false** because the values of translational and rotational kinetic energies depend on the object's shape and mass distribution. 7. **Evaluating the Reason (R)**: - The reason states that "for an object in rolling motion, the magnitude of linear speed and angular speed are equal." This is also **false** because, as established, \(v = r \omega\), indicating they are related but not equal. ### Final Conclusion: Both the assertion and reason are false. ### Answer: Both assertion (A) and reason (R) are false.
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