When a uniform metallic wire is stretche...

When a uniform metallic wire is stretched the lateral strain produced in it is `beta` .if `sigma` and `Y` are the Poisson's ratio and Young's modulus for wire, then elastic potential energy density of Wire is

`(Ybeta^(2))/(2)`

`(Ybeta^(2))/(2sigma^2)`

`(Ysigmabeta^(2))/(2)`

`(Ysigma^(2))/(2beta)`

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