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If the mass of each molecules of a gas i...

If the mass of each molecules of a gas is doubled and speed is halved, find the ratio of initial and final pressure.

Text Solution

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`P= (1)/(3) (M)/(V) v^2`
`P_1 = (1)/(3) (M_2)/(V) V_(1)^(2)`
`P_2 = (1)/(3) (M_2)/(V) v_(2)^(2)`
`(P_1)/(P_2) = (M_1)/(M_2) xx (v_(1)^(2))/(v_(2)^(2))= (M)/(2M)= (M)/(2M) xx (v^2)/((1)/(4) v^2)`
`P_1 : P_ 2 = (4)/(2) = (2)/(1) =2:1`
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